If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-3x-252=0
a = 2; b = -3; c = -252;
Δ = b2-4ac
Δ = -32-4·2·(-252)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-45}{2*2}=\frac{-42}{4} =-10+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+45}{2*2}=\frac{48}{4} =12 $
| F(x)=3x2+12x+7 | | 3.2b-5.7=20.1 | | 6d+136=400 | | -3x^2+19x-43=-2x^2+11-27 | | 32-11x=-3x | | 39-7x=-4(7x+7)=4 | | 3x^2+13x=2x^2+8x | | 9x+26=5 | | 3x^2+17x+25=2x^2+10x+13 | | 2^3x-4=32^x | | 7x-3=-9-10x | | 2x-4=(3x10+2 | | 5x^2+52x+175=0 | | x-(3x-4)=3(3) | | 2x^2+5x-8=x^2+3x-5 | | 1/2(10x+8)–4=100 | | 43=d/1.20+d/1.20^2 | | 2x^2+5x-8=x^2+3x-5 | | 4(2q+1/3+5)=48 | | 5d+30=55. | | 1=5x-19 | | 2x^2-5x-8=x^2+3x-5 | | 4(x+1)=2x-18 | | 3/4=1/3y | | 6x+2+88=12x-2 | | 6x+2+8=12x-2 | | 2x^2-8x-9=x^2-5x-5 | | 10=10-9x | | -2x^2-11x+14=-x^2-7x+9 | | 39x+31=577 | | 4x-12+63=6x+20 | | x+1/5+x/2=10 |